Program For Bisection Method In Fortran Compiler
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Fortran Compiler For Windows
Bisection Method The bisection method in # mathematics is a # root-finding method which repeatedly bisects an # interval and then selects a subinterval in which a # root must lie for further processing. Nd bhatt engineering drawing ebook pdf free. It is a very simple and robust method, but it is also relatively slow. Because of this, it is often used to obtain a rough.
Intel Fortran Compiler For Linux
I'm rusty with fortran and programming in general. I can't see my 'error' in a code that I wrote from scratch.
Basically I wanted to get some fun and solve for a temperature in thermodynamics where I must get 'T_f' which appear in a transcendental equation: ##Aln left ( frac{T_f^2}{T_1T_2} right )+2B[2T_f-(T_1T_2)]=0##.
Where T_1 is worth 100, T_2 is worth 200, A=2 and B=0.005.
Here is my code: that I compile along with The problem is that for the values I said above, I get the message 'There's an even number of root(s) in that interval'. Thus apparently the condition f(a)*f(b)>0 is satisfied. However when I enter the numbers in my pocket calculator I get f(a)=-2.3862.. and f(b)=2.3862.. where I truncated both values. Thus the condition is not satisfied.
I really don't see what's wrong. Any idea?
Edit: I tried with many different values for a and b. I even changed t_1 and t_2, same message.
Edit2: I've just tested the values of fa and fb. It thinks they are worth infinity. Going to check this out.
Edit3: No idea why it thinks they are worth infinity. o_0.
Edit4: ok it does not plug in t_1 and t_2 inside my function.
Basically I wanted to get some fun and solve for a temperature in thermodynamics where I must get 'T_f' which appear in a transcendental equation: ##Aln left ( frac{T_f^2}{T_1T_2} right )+2B[2T_f-(T_1T_2)]=0##.
Where T_1 is worth 100, T_2 is worth 200, A=2 and B=0.005.
Here is my code: that I compile along with The problem is that for the values I said above, I get the message 'There's an even number of root(s) in that interval'. Thus apparently the condition f(a)*f(b)>0 is satisfied. However when I enter the numbers in my pocket calculator I get f(a)=-2.3862.. and f(b)=2.3862.. where I truncated both values. Thus the condition is not satisfied.
I really don't see what's wrong. Any idea?
Edit: I tried with many different values for a and b. I even changed t_1 and t_2, same message.
Edit2: I've just tested the values of fa and fb. It thinks they are worth infinity. Going to check this out.
Edit3: No idea why it thinks they are worth infinity. o_0.
Edit4: ok it does not plug in t_1 and t_2 inside my function.